Integrand size = 23, antiderivative size = 161 \[ \int \frac {a+b \arctan (c x)}{x^3 (d+i c d x)} \, dx=-\frac {b c}{2 d x}-\frac {b c^2 \arctan (c x)}{2 d}-\frac {a+b \arctan (c x)}{2 d x^2}+\frac {i c (a+b \arctan (c x))}{d x}-\frac {i b c^2 \log (x)}{d}+\frac {i b c^2 \log \left (1+c^2 x^2\right )}{2 d}-\frac {c^2 (a+b \arctan (c x)) \log \left (2-\frac {2}{1+i c x}\right )}{d}-\frac {i b c^2 \operatorname {PolyLog}\left (2,-1+\frac {2}{1+i c x}\right )}{2 d} \]
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Time = 0.17 (sec) , antiderivative size = 161, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.435, Rules used = {4990, 4946, 331, 209, 272, 36, 29, 31, 4988, 2497} \[ \int \frac {a+b \arctan (c x)}{x^3 (d+i c d x)} \, dx=-\frac {c^2 \log \left (2-\frac {2}{1+i c x}\right ) (a+b \arctan (c x))}{d}-\frac {a+b \arctan (c x)}{2 d x^2}+\frac {i c (a+b \arctan (c x))}{d x}-\frac {b c^2 \arctan (c x)}{2 d}-\frac {i b c^2 \operatorname {PolyLog}\left (2,\frac {2}{i c x+1}-1\right )}{2 d}+\frac {i b c^2 \log \left (c^2 x^2+1\right )}{2 d}-\frac {i b c^2 \log (x)}{d}-\frac {b c}{2 d x} \]
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Rule 29
Rule 31
Rule 36
Rule 209
Rule 272
Rule 331
Rule 2497
Rule 4946
Rule 4988
Rule 4990
Rubi steps \begin{align*} \text {integral}& = -\left ((i c) \int \frac {a+b \arctan (c x)}{x^2 (d+i c d x)} \, dx\right )+\frac {\int \frac {a+b \arctan (c x)}{x^3} \, dx}{d} \\ & = -\frac {a+b \arctan (c x)}{2 d x^2}-c^2 \int \frac {a+b \arctan (c x)}{x (d+i c d x)} \, dx-\frac {(i c) \int \frac {a+b \arctan (c x)}{x^2} \, dx}{d}+\frac {(b c) \int \frac {1}{x^2 \left (1+c^2 x^2\right )} \, dx}{2 d} \\ & = -\frac {b c}{2 d x}-\frac {a+b \arctan (c x)}{2 d x^2}+\frac {i c (a+b \arctan (c x))}{d x}-\frac {c^2 (a+b \arctan (c x)) \log \left (2-\frac {2}{1+i c x}\right )}{d}-\frac {\left (i b c^2\right ) \int \frac {1}{x \left (1+c^2 x^2\right )} \, dx}{d}-\frac {\left (b c^3\right ) \int \frac {1}{1+c^2 x^2} \, dx}{2 d}+\frac {\left (b c^3\right ) \int \frac {\log \left (2-\frac {2}{1+i c x}\right )}{1+c^2 x^2} \, dx}{d} \\ & = -\frac {b c}{2 d x}-\frac {b c^2 \arctan (c x)}{2 d}-\frac {a+b \arctan (c x)}{2 d x^2}+\frac {i c (a+b \arctan (c x))}{d x}-\frac {c^2 (a+b \arctan (c x)) \log \left (2-\frac {2}{1+i c x}\right )}{d}-\frac {i b c^2 \operatorname {PolyLog}\left (2,-1+\frac {2}{1+i c x}\right )}{2 d}-\frac {\left (i b c^2\right ) \text {Subst}\left (\int \frac {1}{x \left (1+c^2 x\right )} \, dx,x,x^2\right )}{2 d} \\ & = -\frac {b c}{2 d x}-\frac {b c^2 \arctan (c x)}{2 d}-\frac {a+b \arctan (c x)}{2 d x^2}+\frac {i c (a+b \arctan (c x))}{d x}-\frac {c^2 (a+b \arctan (c x)) \log \left (2-\frac {2}{1+i c x}\right )}{d}-\frac {i b c^2 \operatorname {PolyLog}\left (2,-1+\frac {2}{1+i c x}\right )}{2 d}-\frac {\left (i b c^2\right ) \text {Subst}\left (\int \frac {1}{x} \, dx,x,x^2\right )}{2 d}+\frac {\left (i b c^4\right ) \text {Subst}\left (\int \frac {1}{1+c^2 x} \, dx,x,x^2\right )}{2 d} \\ & = -\frac {b c}{2 d x}-\frac {b c^2 \arctan (c x)}{2 d}-\frac {a+b \arctan (c x)}{2 d x^2}+\frac {i c (a+b \arctan (c x))}{d x}-\frac {i b c^2 \log (x)}{d}+\frac {i b c^2 \log \left (1+c^2 x^2\right )}{2 d}-\frac {c^2 (a+b \arctan (c x)) \log \left (2-\frac {2}{1+i c x}\right )}{d}-\frac {i b c^2 \operatorname {PolyLog}\left (2,-1+\frac {2}{1+i c x}\right )}{2 d} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.14 (sec) , antiderivative size = 178, normalized size of antiderivative = 1.11 \[ \int \frac {a+b \arctan (c x)}{x^3 (d+i c d x)} \, dx=-\frac {\frac {a+b \arctan (c x)}{x^2}-\frac {2 i c (a+b \arctan (c x))}{x}+\frac {b c \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},1,\frac {1}{2},-c^2 x^2\right )}{x}+2 a c^2 \log (x)+2 c^2 (a+b \arctan (c x)) \log \left (\frac {2 i}{i-c x}\right )+i b c^2 \left (2 \log (x)-\log \left (1+c^2 x^2\right )\right )+i b c^2 \operatorname {PolyLog}(2,-i c x)-i b c^2 \operatorname {PolyLog}(2,i c x)+i b c^2 \operatorname {PolyLog}\left (2,\frac {i+c x}{-i+c x}\right )}{2 d} \]
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Time = 1.03 (sec) , antiderivative size = 251, normalized size of antiderivative = 1.56
method | result | size |
derivativedivides | \(c^{2} \left (-\frac {a}{2 d \,c^{2} x^{2}}+\frac {i a}{d c x}-\frac {a \ln \left (c x \right )}{d}+\frac {a \ln \left (c^{2} x^{2}+1\right )}{2 d}+\frac {i a \arctan \left (c x \right )}{d}+\frac {b \left (-\frac {\arctan \left (c x \right )}{2 c^{2} x^{2}}+\frac {i \arctan \left (c x \right )}{c x}-\arctan \left (c x \right ) \ln \left (c x \right )+\arctan \left (c x \right ) \ln \left (c x -i\right )-i \ln \left (c x \right )-\frac {1}{2 c x}+\frac {i \ln \left (c^{2} x^{2}+1\right )}{2}-\frac {\arctan \left (c x \right )}{2}-\frac {i \ln \left (c x \right ) \ln \left (i c x +1\right )}{2}+\frac {i \ln \left (c x \right ) \ln \left (-i c x +1\right )}{2}-\frac {i \operatorname {dilog}\left (i c x +1\right )}{2}+\frac {i \operatorname {dilog}\left (-i c x +1\right )}{2}-\frac {i \left (\operatorname {dilog}\left (-\frac {i \left (c x +i\right )}{2}\right )+\ln \left (c x -i\right ) \ln \left (-\frac {i \left (c x +i\right )}{2}\right )\right )}{2}+\frac {i \ln \left (c x -i\right )^{2}}{4}\right )}{d}\right )\) | \(251\) |
default | \(c^{2} \left (-\frac {a}{2 d \,c^{2} x^{2}}+\frac {i a}{d c x}-\frac {a \ln \left (c x \right )}{d}+\frac {a \ln \left (c^{2} x^{2}+1\right )}{2 d}+\frac {i a \arctan \left (c x \right )}{d}+\frac {b \left (-\frac {\arctan \left (c x \right )}{2 c^{2} x^{2}}+\frac {i \arctan \left (c x \right )}{c x}-\arctan \left (c x \right ) \ln \left (c x \right )+\arctan \left (c x \right ) \ln \left (c x -i\right )-i \ln \left (c x \right )-\frac {1}{2 c x}+\frac {i \ln \left (c^{2} x^{2}+1\right )}{2}-\frac {\arctan \left (c x \right )}{2}-\frac {i \ln \left (c x \right ) \ln \left (i c x +1\right )}{2}+\frac {i \ln \left (c x \right ) \ln \left (-i c x +1\right )}{2}-\frac {i \operatorname {dilog}\left (i c x +1\right )}{2}+\frac {i \operatorname {dilog}\left (-i c x +1\right )}{2}-\frac {i \left (\operatorname {dilog}\left (-\frac {i \left (c x +i\right )}{2}\right )+\ln \left (c x -i\right ) \ln \left (-\frac {i \left (c x +i\right )}{2}\right )\right )}{2}+\frac {i \ln \left (c x -i\right )^{2}}{4}\right )}{d}\right )\) | \(251\) |
parts | \(-\frac {a}{2 d \,x^{2}}+\frac {i a c}{d x}-\frac {a \,c^{2} \ln \left (x \right )}{d}+\frac {c^{2} a \ln \left (c^{2} x^{2}+1\right )}{2 d}+\frac {i c^{2} a \arctan \left (c x \right )}{d}+\frac {b \,c^{2} \left (-\frac {\arctan \left (c x \right )}{2 c^{2} x^{2}}+\frac {i \arctan \left (c x \right )}{c x}-\arctan \left (c x \right ) \ln \left (c x \right )+\arctan \left (c x \right ) \ln \left (c x -i\right )-i \ln \left (c x \right )-\frac {1}{2 c x}+\frac {i \ln \left (c^{2} x^{2}+1\right )}{2}-\frac {\arctan \left (c x \right )}{2}-\frac {i \ln \left (c x \right ) \ln \left (i c x +1\right )}{2}+\frac {i \ln \left (c x \right ) \ln \left (-i c x +1\right )}{2}-\frac {i \operatorname {dilog}\left (i c x +1\right )}{2}+\frac {i \operatorname {dilog}\left (-i c x +1\right )}{2}-\frac {i \left (\operatorname {dilog}\left (-\frac {i \left (c x +i\right )}{2}\right )+\ln \left (c x -i\right ) \ln \left (-\frac {i \left (c x +i\right )}{2}\right )\right )}{2}+\frac {i \ln \left (c x -i\right )^{2}}{4}\right )}{d}\) | \(252\) |
risch | \(-\frac {i c^{2} b \operatorname {dilog}\left (\frac {1}{2}-\frac {i c x}{2}\right )}{2 d}-\frac {i b \ln \left (-i c x +1\right )}{4 d \,x^{2}}-\frac {i c^{2} b \ln \left (-i c x \right )}{4 d}+\frac {i c^{2} b \ln \left (-i c x +1\right )}{4 d}-\frac {3 b \,c^{2} \arctan \left (c x \right )}{4 d}+\frac {b c \ln \left (i c x +1\right )}{2 d x}-\frac {b c}{2 d x}+\frac {i c^{2} a \arctan \left (c x \right )}{d}-\frac {a}{2 d \,x^{2}}+\frac {i c^{2} \operatorname {dilog}\left (-i c x +1\right ) b}{2 d}-\frac {c^{2} \ln \left (-i c x \right ) a}{d}+\frac {c^{2} a \ln \left (c^{2} x^{2}+1\right )}{2 d}+\frac {i c^{2} b \ln \left (\frac {1}{2}+\frac {i c x}{2}\right ) \ln \left (-i c x +1\right )}{2 d}-\frac {i b \,c^{2} \operatorname {dilog}\left (i c x +1\right )}{2 d}+\frac {i a c}{d x}+\frac {i b \ln \left (i c x +1\right )}{4 d \,x^{2}}-\frac {c b \ln \left (-i c x +1\right )}{2 d x}-\frac {i c^{2} \ln \left (\frac {1}{2}-\frac {i c x}{2}\right ) \ln \left (\frac {1}{2}+\frac {i c x}{2}\right ) b}{2 d}-\frac {3 i b \,c^{2} \ln \left (i c x \right )}{4 d}-\frac {i b \,c^{2} \ln \left (i c x +1\right )^{2}}{4 d}+\frac {3 i b \,c^{2} \ln \left (c^{2} x^{2}+1\right )}{8 d}\) | \(361\) |
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Time = 0.25 (sec) , antiderivative size = 130, normalized size of antiderivative = 0.81 \[ \int \frac {a+b \arctan (c x)}{x^3 (d+i c d x)} \, dx=\frac {2 i \, b c^{2} x^{2} {\rm Li}_2\left (\frac {c x + i}{c x - i} + 1\right ) - 4 \, {\left (a + i \, b\right )} c^{2} x^{2} \log \left (x\right ) + i \, b c^{2} x^{2} \log \left (\frac {c x + i}{c}\right ) + {\left (4 \, a + 3 i \, b\right )} c^{2} x^{2} \log \left (\frac {c x - i}{c}\right ) - 2 \, {\left (-2 i \, a + b\right )} c x - {\left (2 \, b c x + i \, b\right )} \log \left (-\frac {c x + i}{c x - i}\right ) - 2 \, a}{4 \, d x^{2}} \]
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\[ \int \frac {a+b \arctan (c x)}{x^3 (d+i c d x)} \, dx=- \frac {i \left (\int \frac {a}{c x^{4} - i x^{3}}\, dx + \int \frac {b \operatorname {atan}{\left (c x \right )}}{c x^{4} - i x^{3}}\, dx\right )}{d} \]
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\[ \int \frac {a+b \arctan (c x)}{x^3 (d+i c d x)} \, dx=\int { \frac {b \arctan \left (c x\right ) + a}{{\left (i \, c d x + d\right )} x^{3}} \,d x } \]
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\[ \int \frac {a+b \arctan (c x)}{x^3 (d+i c d x)} \, dx=\int { \frac {b \arctan \left (c x\right ) + a}{{\left (i \, c d x + d\right )} x^{3}} \,d x } \]
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Timed out. \[ \int \frac {a+b \arctan (c x)}{x^3 (d+i c d x)} \, dx=\int \frac {a+b\,\mathrm {atan}\left (c\,x\right )}{x^3\,\left (d+c\,d\,x\,1{}\mathrm {i}\right )} \,d x \]
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